We know that
$\displaystyle\frac{1}{1-x}=1+x+{{x}^{2}}+{{x}^{3}}+...+{{x}^{n-1}}+...$
for $x\in\left(-1,1\right)$.
**Using this fact, find the function that corresponds to the following series.**
$\displaystyle -x-\frac{{{x}^{2}}}{2}-\frac{{{x}^3}}{3}-...-\frac{{{x}^{n}}}{n}-...$
[[☃ radio 1]]