We know that $\displaystyle\frac{1}{1-x}=1+x+{{x}^{2}}+{{x}^{3}}+...+{{x}^{n-1}}+...$ for $x\in\left(-1,1\right)$. **Using this fact, find the function that corresponds to the following series.** $\displaystyle -x-\frac{{{x}^{2}}}{2}-\frac{{{x}^3}}{3}-...-\frac{{{x}^{n}}}{n}-...$ [[☃ radio 1]]