$\displaystyle\sum\limits_{n=0}^{\infty }{\frac{{{\left( -1 \right)}^{n+1}}}{(2n+1)!}}$ is approximated using the partial sum $\displaystyle\sum\limits_{n=0}^{3}{\frac{{{\left( -1 \right)}^{n+1}}}{(2n+1)!}}$.
**Complete the sentence about the error of the approximation.**
The error bound is
[[☃ dropdown 1]] and hence the approximation is an [[☃ dropdown 2]].
**What is the absolute value of the error bound?**
*Round to six decimal places.*
[[☃ input-number 1]]