The $n\text{th}$ partial sum of the series $\sum\limits_{n=1}^{\infty }{{{a}_{n}}}$ is given by $\displaystyle{{S}_{n}}=6-\frac{3}{{{n}^{2}}}$. $\displaystyle\sum\limits_{n=1}^{9}{{{a}_{n}}}=$ [[☃ input-number 1]]