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Definite integral basics challenge

Given:   9k2kg(x)dx=4   ~~\displaystyle \int_{9k}^{2k}g(x)\,dx=-4~~~ and    6k9kg(x)dx=1~~~\displaystyle \int_{6k}^{9k}g(x)\,dx=-1\,, where  k>0~k>0\,.
What is the value of   2k6kg(x)dx~~\displaystyle \int_{2k}^{6k}g(x)\,dx\,?