Product rule

- Let $f$ be a function such that $f(-1)=3$ and $f'(-1)=5$. - Let $g$ be the function $g(x)=\dfrac{1}{x}$. Let $F$ be a function defined as $F(x)=f(x)\cdot g(x)$. $F'(-1)=$ [[☃ numeric-input 1]]