Lloyd tried to evaluate $(-t)^3$ where $t = -4$.
$\qquad\begin{align}
&(-t)^3\\\\
\\
=&(-(-4))^3&\green{\text{Step } 1}\\\\
\\
=&(-4)^3&\blue{\text{Step } 2}\\\\
\\
=&-64&\purple{\text{Step } 3} \\\\
\end{align}$
**Find Lloyd's mistake.**
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