Free One sample intervals for proportions Practice Problems • Learn To Be

Alessandra conducts a survey to estimate the proportion of customers who are satisfied with the quality of the meat at a local supermarket. In a random sample of

45

customers,

60\%

said that they are satisfied with the supermarket's meat quality.

Assuming that all the necessary conditions are met, determine a $90\%$ confidence interval for the proportion of customers at this supermarket who are satisfied with the quality of the meat.

Choose 1 answer:

A
$0.60\pm1.28\dfrac{\sqrt{\left(0.60\right)\left(0.40\right)}}{45}$
B
$0.60\pm1.28\sqrt{\dfrac{\left(0.60\right)\left(0.40\right)}{45}}$
C
$0.60\pm1.65\dfrac{\sqrt{\left(0.60\right)\left(0.40\right)}}{45}$
D
$0.60\pm1.65\sqrt{\dfrac{\left(0.60\right)\left(0.40\right)}{45}}$
E
$0.60\pm0.90\dfrac{\sqrt{\left(0.60\right)\left(0.40\right)}}{45}$

One sample intervals for proportions

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